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## What is the pH of a solution with a concentration of 1.0 x 10 3 M?

The pH of 1.0xd710u22123M 1.0 xd7 10 u2212 3 M HCl solution. The concentration of H3O+ H 3 O + will be 1.0xd710u22123M 1.0 xd7 10 u2212 3 M . Therefore, the pH of the HCl solution comes out to **be 3**

## How do you find the pH from molarity of hno3?

**Divide the number of moles of nitric acid with the volume of solution to obtain the molarity of nitric acid solution. From the concentration of nitric acid, calculate the concentration of hydrogen ions. Use the concentration of hydrogen ions to calculate the pH of the solution. Thus, the pH of the solution is 1.6021.**

## How do you calculate the pH of a mole given the solution?

To calculate the pH of an aqueous solution you need to know the concentration of the hydronium ion in moles per liter (molarity). The pH is then calculated using the expression: **pH – log [H3O+].**

## What is the pH of 1.0 x10 3 mol dm 3 sodium?

And thus our definining relationship: **pH+pOH14 .**

## What is the pH of a solution with a pH -] of 1.0 x 10 3?

The pH is **9.**

## What is the pH of a solution of 1.0 10 − 9 M HCl?

6.99

## What is the pH of H +] 1.0 x 10 10 m?

The pH of a solution with the [H + ] 1 xd7 10 -2 M is 2 and the pH of a solution with the [H + ] 1 xd7 10 -10 M is **10.**

## What is the pH of a 1 M solution of HNO3?

The obvious answer is a **pH of zero when substituting the 1M value into the definition of pH. However, the acidity relates to the hydrated hydrogen ion H3O+.**

## How do you calculate pH from molarity?

To calculate the pH of an aqueous solution you need to know the concentration of the hydronium ion in moles per liter (molarity). The pH is then calculated using the expression: **pH – log [H3O+].**

## What is the pH of a 0.20 M solution of HNO3?

0.7

## What is the pH of 0.1 m of HNO3?

So, concentration of hydrogen ions in $HN{{O}_{3}}$ is 0.1 M. And now by using this formula we will find pOH. So, from this we can say that pH of $HN{{O}_{3}}$ is 1 and pOH of $HN{{O}_{3}}$ is **13**